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131012224203319 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101011011101000110111
3122011212122110011102120201221
4131302132221011123220313
5114133001013344001234
61142350103535331211
736411215022365314
oct3562365105335067
9564778404376657
10131012224203319
1138820a77098a98
121283b068980b07
135814527295214
14244d04dd05d0b
151022dde0baeb4
hex7727a915ba37

131012224203319 has 2 divisors, whose sum is σ = 131012224203320. Its totient is φ = 131012224203318.

The previous prime is 131012224203317. The next prime is 131012224203347. The reversal of 131012224203319 is 913302422210131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131012224203319 - 21 = 131012224203317 is a prime.

It is a super-2 number, since 2×1310122242033192 (a number of 29 digits) contains 22 as substring.

Together with 131012224203317, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012224203317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112101659 + 65506112101660.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112101660).

Almost surely, 2131012224203319 is an apocalyptic number.

131012224203319 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224203319 is an equidigital number, since it uses as much as digits as its factorization.

131012224203319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 34.

The spelling of 131012224203319 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred three thousand, three hundred nineteen".