Base | Representation |
---|---|
bin | 1011111010100101111000… |
… | …1011000001100110011000 |
3 | 1201101110120020222120101002 |
4 | 2332221132023001212120 |
5 | 3204122304412414430 |
6 | 43510342211044132 |
7 | 2521350461202416 |
oct | 276513613014630 |
9 | 51343506876332 |
10 | 13101230201240 |
11 | 41a122299a235 |
12 | 15771335a0648 |
13 | 740596304a8c |
14 | 3341625d82b6 |
15 | 17abd68c5845 |
hex | bea5e2c1998 |
13101230201240 has 32 divisors (see below), whose sum is σ = 29500601351760. Its totient is φ = 5236432809600.
The previous prime is 13101230201239. The next prime is 13101230201317. The reversal of 13101230201240 is 4210203210131.
13101230201240 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126799931 + ... + 126903210.
Almost surely, 213101230201240 is an apocalyptic number.
13101230201240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13101230201240 is an abundant number, since it is smaller than the sum of its proper divisors (16399371150520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101230201240 is a wasteful number, since it uses less digits than its factorization.
13101230201240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253704443 (or 253704439 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 13101230201240 its reverse (4210203210131), we get a palindrome (17311433411371).
The spelling of 13101230201240 in words is "thirteen trillion, one hundred one billion, two hundred thirty million, two hundred one thousand, two hundred forty".
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