Base | Representation |
---|---|
bin | 1011111010100101111011… |
… | …1011110110110100010110 |
3 | 1201101110121011001220220021 |
4 | 2332221132323312310112 |
5 | 3204122321202032014 |
6 | 43510343345255354 |
7 | 2521351005046000 |
oct | 276513673666426 |
9 | 51343534056807 |
10 | 13101243002134 |
11 | 41a122a142791 |
12 | 157713793455a |
13 | 740598b67481 |
14 | 3341641ab370 |
15 | 17abd7aa3624 |
hex | bea5eef6d16 |
13101243002134 has 32 divisors (see below), whose sum is σ = 22983671692800. Its totient is φ = 5598637294824.
The previous prime is 13101243002119. The next prime is 13101243002161. The reversal of 13101243002134 is 43120034210131.
It is a junction number, because it is equal to n+sod(n) for n = 13101243002099 and 13101243002108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27280722 + ... + 27756805.
It is an arithmetic number, because the mean of its divisors is an integer number (718239740400).
Almost surely, 213101243002134 is an apocalyptic number.
13101243002134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13101243002134 is a deficient number, since it is larger than the sum of its proper divisors (9882428690666).
13101243002134 is an equidigital number, since it uses as much as digits as its factorization.
13101243002134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55037897 (or 55037883 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13101243002134 its reverse (43120034210131), we get a palindrome (56221277212265).
The spelling of 13101243002134 in words is "thirteen trillion, one hundred one billion, two hundred forty-three million, two thousand, one hundred thirty-four".
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