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1310131021421 is a prime number
BaseRepresentation
bin10011000100001001111…
…001001110011001101101
311122020200021122122221202
4103010021321032121231
5132431122020141141
62441511010335245
7163440160640105
oct23041171163155
94566607578852
101310131021421
11465694896572
12191ab428a525
1396710c9a281
14475a6c96205
152412d56449b
hex13109e4e66d

1310131021421 has 2 divisors, whose sum is σ = 1310131021422. Its totient is φ = 1310131021420.

The previous prime is 1310131021363. The next prime is 1310131021471. The reversal of 1310131021421 is 1241201310131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1186465562500 + 123665458921 = 1089250^2 + 351661^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310131021421 - 26 = 1310131021357 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310131021393 and 1310131021402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310131021471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065510710 + 655065510711.

It is an arithmetic number, because the mean of its divisors is an integer number (655065510711).

Almost surely, 21310131021421 is an apocalyptic number.

It is an amenable number.

1310131021421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310131021421 is an equidigital number, since it uses as much as digits as its factorization.

1310131021421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1310131021421 its reverse (1241201310131), we get a palindrome (2551332331552).

The spelling of 1310131021421 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, twenty-one thousand, four hundred twenty-one".