Base | Representation |
---|---|
bin | 10011000100001001111… |
… | …001001110011010011111 |
3 | 11122020200021122200000121 |
4 | 103010021321032122133 |
5 | 132431122020141341 |
6 | 2441511010335411 |
7 | 163440160640206 |
oct | 23041171163237 |
9 | 4566607580017 |
10 | 1310131021471 |
11 | 465694896608 |
12 | 191ab428a567 |
13 | 96710c9a2bc |
14 | 475a6c9623d |
15 | 2412d5644d1 |
hex | 13109e4e69f |
1310131021471 has 2 divisors, whose sum is σ = 1310131021472. Its totient is φ = 1310131021470.
The previous prime is 1310131021421. The next prime is 1310131021481. The reversal of 1310131021471 is 1741201310131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310131021471 is a prime.
It is a super-3 number, since 3×13101310214713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310131021421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065510735 + 655065510736.
It is an arithmetic number, because the mean of its divisors is an integer number (655065510736).
Almost surely, 21310131021471 is an apocalyptic number.
1310131021471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310131021471 is an equidigital number, since it uses as much as digits as its factorization.
1310131021471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 1310131021471 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, twenty-one thousand, four hundred seventy-one".
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