Base | Representation |
---|---|
bin | 1011111010100110001100… |
… | …0100001101001111001111 |
3 | 1201101110202222110121200021 |
4 | 2332221203010031033033 |
5 | 3204122441422044413 |
6 | 43510354302443011 |
7 | 2521352506056355 |
oct | 276514304151717 |
9 | 51343688417607 |
10 | 13101312299983 |
11 | 41a1265274236 |
12 | 1577156b93467 |
13 | 7405aa31b50b |
14 | 33416d4897d5 |
15 | 17abddbe118d |
hex | bea6310d3cf |
13101312299983 has 2 divisors, whose sum is σ = 13101312299984. Its totient is φ = 13101312299982.
The previous prime is 13101312299981. The next prime is 13101312300017. The reversal of 13101312299983 is 38999221310131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13101312299983 - 21 = 13101312299981 is a prime.
Together with 13101312299981, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13101312299983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101312299981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550656149991 + 6550656149992.
It is an arithmetic number, because the mean of its divisors is an integer number (6550656149992).
Almost surely, 213101312299983 is an apocalyptic number.
13101312299983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101312299983 is an equidigital number, since it uses as much as digits as its factorization.
13101312299983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 52.
The spelling of 13101312299983 in words is "thirteen trillion, one hundred one billion, three hundred twelve million, two hundred ninety-nine thousand, nine hundred eighty-three".
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