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13101353431 is a prime number
BaseRepresentation
bin11000011001110011…
…01100100111010111
31020211001111201020021
430030321230213113
5203312421302211
610004011250011
7642443444455
oct141471544727
936731451207
1013101353431
115613410821
122657749907
13130a39a54a
148c3dcd9d5
1551a2c2771
hex30ce6c9d7

13101353431 has 2 divisors, whose sum is σ = 13101353432. Its totient is φ = 13101353430.

The previous prime is 13101353413. The next prime is 13101353459. The reversal of 13101353431 is 13435310131.

Together with previous prime (13101353413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13101353431 - 211 = 13101351383 is a prime.

It is a super-2 number, since 2×131013534312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13101353396 and 13101353405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101353231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550676715 + 6550676716.

It is an arithmetic number, because the mean of its divisors is an integer number (6550676716).

Almost surely, 213101353431 is an apocalyptic number.

13101353431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101353431 is an equidigital number, since it uses as much as digits as its factorization.

13101353431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 13101353431 its reverse (13435310131), we get a palindrome (26536663562).

The spelling of 13101353431 in words is "thirteen billion, one hundred one million, three hundred fifty-three thousand, four hundred thirty-one".