Search a number
-
+
13101404020125 = 353181810123827
BaseRepresentation
bin1011111010100110100010…
…0010000101110110011101
31201101111000101001111001120
42332221220202011312131
53204123133412121000
643510411340401153
72521355001505131
oct276515042056635
951344011044046
1013101404020125
1141a130201aa03
1215771818461b9
137405c33233a5
1433417b7233c1
1517abe6cac6a0
hexbea68885d9d

13101404020125 has 64 divisors (see below), whose sum is σ = 21924808459008. Its totient is φ = 6947661600000.

The previous prime is 13101404020073. The next prime is 13101404020129. The reversal of 13101404020125 is 52102040410131.

It is not a de Polignac number, because 13101404020125 - 214 = 13101404003741 is a prime.

It is a super-2 number, since 2×131014040201252 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13101404020095 and 13101404020104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101404020129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 549843462 + ... + 549867288.

It is an arithmetic number, because the mean of its divisors is an integer number (342575132172).

Almost surely, 213101404020125 is an apocalyptic number.

13101404020125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13101404020125 is a deficient number, since it is larger than the sum of its proper divisors (8823404438883).

13101404020125 is a wasteful number, since it uses less digits than its factorization.

13101404020125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32127 (or 32117 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 13101404020125 its reverse (52102040410131), we get a palindrome (65203444430256).

The spelling of 13101404020125 in words is "thirteen trillion, one hundred one billion, four hundred four million, twenty thousand, one hundred twenty-five".

Divisors: 1 3 5 15 25 75 125 181 375 543 905 2715 4525 8101 13575 22625 23827 24303 40505 67875 71481 119135 121515 202525 357405 595675 607575 1012625 1466281 1787025 2978375 3037875 4312687 4398843 7331405 8935125 12938061 21563435 21994215 36657025 64690305 107817175 109971075 183285125 193022527 323451525 539085875 549855375 579067581 965112635 1617257625 2895337905 4825563175 14476689525 24127815875 34937077387 72383447625 104811232161 174685386935 524056160805 873426934675 2620280804025 4367134673375 13101404020125