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13101404020134 = 2315114460710839
BaseRepresentation
bin1011111010100110100010…
…0010000101110110100110
31201101111000101001111001220
42332221220202011312212
53204123133412121014
643510411340401210
72521355001505143
oct276515042056646
951344011044056
1013101404020134
1141a130201aa11
121577181846206
137405c33233b1
1433417b7233ca
1517abe6cac6a9
hexbea68885da6

13101404020134 has 16 divisors (see below), whose sum is σ = 26376336572160. Its totient is φ = 4338213251400.

The previous prime is 13101404020129. The next prime is 13101404020153. The reversal of 13101404020134 is 43102040410131.

13101404020134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7230354514 + ... + 7230356325.

It is an arithmetic number, because the mean of its divisors is an integer number (1648521035760).

Almost surely, 213101404020134 is an apocalyptic number.

13101404020134 is an abundant number, since it is smaller than the sum of its proper divisors (13274932552026).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101404020134 is a wasteful number, since it uses less digits than its factorization.

13101404020134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14460710995.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13101404020134 its reverse (43102040410131), we get a palindrome (56203444430265).

The spelling of 13101404020134 in words is "thirteen trillion, one hundred one billion, four hundred four million, twenty thousand, one hundred thirty-four".

Divisors: 1 2 3 6 151 302 453 906 14460710839 28921421678 43382132517 86764265034 2183567336689 4367134673378 6550702010067 13101404020134