Base | Representation |
---|---|
bin | 11101110010100000101011… |
… | …100000110111000011110111 |
3 | 122011212212002122222002122002 |
4 | 131302200223200313003313 |
5 | 114133020004040302412 |
6 | 1142351105024525515 |
7 | 36411323163125525 |
oct | 3562405340670367 |
9 | 564785078862562 |
10 | 131014412431607 |
11 | 3882199a308321 |
12 | 1283b57978089b |
13 | 58147b5734763 |
14 | 244d1ba79b315 |
15 | 1022ebb25edc2 |
hex | 77282b8370f7 |
131014412431607 has 2 divisors, whose sum is σ = 131014412431608. Its totient is φ = 131014412431606.
The previous prime is 131014412431421. The next prime is 131014412431621. The reversal of 131014412431607 is 706134214410131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131014412431607 - 226 = 131014345322743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131014412431807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65507206215803 + 65507206215804.
It is an arithmetic number, because the mean of its divisors is an integer number (65507206215804).
Almost surely, 2131014412431607 is an apocalyptic number.
131014412431607 is a deficient number, since it is larger than the sum of its proper divisors (1).
131014412431607 is an equidigital number, since it uses as much as digits as its factorization.
131014412431607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 38.
Adding to 131014412431607 its reverse (706134214410131), we get a palindrome (837148626841738).
The spelling of 131014412431607 in words is "one hundred thirty-one trillion, fourteen billion, four hundred twelve million, four hundred thirty-one thousand, six hundred seven".
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