Base | Representation |
---|---|
bin | 111101000000100110… |
… | …1001010101000000100 |
3 | 110112011210002112112201 |
4 | 1322001031022220010 |
5 | 4121310240344030 |
6 | 140104355124244 |
7 | 12315500561041 |
oct | 1720115125004 |
9 | 415153075481 |
10 | 131016731140 |
11 | 506225902a9 |
12 | 214852a3684 |
13 | c47c71c2a9 |
14 | 64ac5301c8 |
15 | 361c24c2ca |
hex | 1e8134aa04 |
131016731140 has 24 divisors (see below), whose sum is σ = 275966373312. Its totient is φ = 52248361440.
The previous prime is 131016731119. The next prime is 131016731141. The reversal of 131016731140 is 41137610131.
It is a super-2 number, since 2×1310167311402 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131016731099 and 131016731108.
It is not an unprimeable number, because it can be changed into a prime (131016731141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9888904 + ... + 9902143.
It is an arithmetic number, because the mean of its divisors is an integer number (11498598888).
Almost surely, 2131016731140 is an apocalyptic number.
131016731140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131016731140 is an abundant number, since it is smaller than the sum of its proper divisors (144949642172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131016731140 is a wasteful number, since it uses less digits than its factorization.
131016731140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19791387 (or 19791385 counting only the distinct ones).
The product of its (nonzero) digits is 1512, while the sum is 28.
The spelling of 131016731140 in words is "one hundred thirty-one billion, sixteen million, seven hundred thirty-one thousand, one hundred forty".
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