Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1011010110111111010011 |
3 | 1201101112121111210112200221 |
4 | 2332222031123112333103 |
5 | 3204130420342343212 |
6 | 43510553011453511 |
7 | 2521406226035065 |
oct | 276521533267723 |
9 | 51345544715627 |
10 | 13102023012307 |
11 | 41a159a46a999 |
12 | 1577314bb7297 |
13 | 74069163b758 |
14 | 3341d9a11735 |
15 | 17ac312cc807 |
hex | bea8d6d6fd3 |
13102023012307 has 2 divisors, whose sum is σ = 13102023012308. Its totient is φ = 13102023012306.
The previous prime is 13102023012271. The next prime is 13102023012341. The reversal of 13102023012307 is 70321032020131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13102023012307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13102023012347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551011506153 + 6551011506154.
It is an arithmetic number, because the mean of its divisors is an integer number (6551011506154).
Almost surely, 213102023012307 is an apocalyptic number.
13102023012307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102023012307 is an equidigital number, since it uses as much as digits as its factorization.
13102023012307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13102023012307 its reverse (70321032020131), we get a palindrome (83423055032438).
The spelling of 13102023012307 in words is "thirteen trillion, one hundred two billion, twenty-three million, twelve thousand, three hundred seven".
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