| Base | Representation |
|---|---|
| bin | 1011111010101000111000… |
| … | …0001111011011110000000 |
| 3 | 1201101112122012211020020110 |
| 4 | 2332222032001323132000 |
| 5 | 3204130430434420300 |
| 6 | 43510554012311320 |
| 7 | 2521406411005650 |
| oct | 276521601733600 |
| 9 | 51345565736213 |
| 10 | 13102033123200 |
| 11 | 41a15a51463aa |
| 12 | 1577318472540 |
| 13 | 74069376b928 |
| 14 | 3341db0c4360 |
| 15 | 17ac32128550 |
| hex | bea8e07b780 |
13102033123200 has 384 divisors, whose sum is σ = 49327612830720. Its totient is φ = 2994275819520.
The previous prime is 13102033123169. The next prime is 13102033123271. The reversal of 13102033123200 is 232133020131.
13102033123200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (384).
It is a super-2 number, since 2×131020331232002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 593835369 + ... + 593857431.
It is an arithmetic number, because the mean of its divisors is an integer number (128457325080).
Almost surely, 213102033123200 is an apocalyptic number.
13102033123200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13102033123200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24663806415360).
13102033123200 is an abundant number, since it is smaller than the sum of its proper divisors (36225579707520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102033123200 is a wasteful number, since it uses less digits than its factorization.
13102033123200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30934 (or 30917 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13102033123200 its reverse (232133020131), we get a palindrome (13334166143331).
The spelling of 13102033123200 in words is "thirteen trillion, one hundred two billion, thirty-three million, one hundred twenty-three thousand, two hundred".
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