Base | Representation |
---|---|
bin | 10011000100001110010… |
… | …000011011010010110000 |
3 | 11122020212101101011002202 |
4 | 103010032100123102300 |
5 | 132431244234244100 |
6 | 2441522143202332 |
7 | 163442040023636 |
oct | 23041620332260 |
9 | 4566771334082 |
10 | 1310204212400 |
11 | 465722136a86 |
12 | 191b148a63a8 |
13 | 967231b5345 |
14 | 475b28a9356 |
15 | 24134bc07d5 |
hex | 1310e41b4b0 |
1310204212400 has 60 divisors (see below), whose sum is σ = 3256309291200. Its totient is φ = 506009898240.
The previous prime is 1310204212399. The next prime is 1310204212409. The reversal of 1310204212400 is 42124020131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (1310204212409) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56462720 + ... + 56485919.
It is an arithmetic number, because the mean of its divisors is an integer number (54271821520).
Almost surely, 21310204212400 is an apocalyptic number.
1310204212400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310204212400 is an abundant number, since it is smaller than the sum of its proper divisors (1946105078800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310204212400 is a wasteful number, since it uses less digits than its factorization.
1310204212400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112948686 (or 112948675 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1310204212400 its reverse (42124020131), we get a palindrome (1352328232531).
The spelling of 1310204212400 in words is "one trillion, three hundred ten billion, two hundred four million, two hundred twelve thousand, four hundred".
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