Base | Representation |
---|---|
bin | 11101110010100110010010… |
… | …110111101000010111001111 |
3 | 122011220102122211120111122021 |
4 | 131302212102313220113033 |
5 | 114133114331000440023 |
6 | 1142353543155031011 |
7 | 36411625451524042 |
oct | 3562462267502717 |
9 | 564812584514567 |
10 | 131020441421263 |
11 | 388245035394a9 |
12 | 1284078089b467 |
13 | 5815236810664 |
14 | 244d5cd394c59 |
15 | 10232206c235d |
hex | 772992de85cf |
131020441421263 has 2 divisors, whose sum is σ = 131020441421264. Its totient is φ = 131020441421262.
The previous prime is 131020441421227. The next prime is 131020441421281. The reversal of 131020441421263 is 362124144020131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131020441421263 - 221 = 131020439324111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131020441421213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510220710631 + 65510220710632.
It is an arithmetic number, because the mean of its divisors is an integer number (65510220710632).
Almost surely, 2131020441421263 is an apocalyptic number.
131020441421263 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020441421263 is an equidigital number, since it uses as much as digits as its factorization.
131020441421263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 131020441421263 its reverse (362124144020131), we get a palindrome (493144585441394).
The spelling of 131020441421263 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-one million, four hundred twenty-one thousand, two hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •