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131020443431231 is a prime number
BaseRepresentation
bin11101110010100110010010…
…111111010011000100111111
3122011220102122222100121210112
4131302212102333103010333
5114133114332004244411
61142353543310100235
736411625504565024
oct3562462277230477
9564812588317715
10131020443431231
1138824504691632
12128407814aa67b
1358152370654a3
14244d5cd75954b
15102322096cb8b
hex772992fd313f

131020443431231 has 2 divisors, whose sum is σ = 131020443431232. Its totient is φ = 131020443431230.

The previous prime is 131020443431221. The next prime is 131020443431243. The reversal of 131020443431231 is 132134344020131.

It is a weak prime.

It is an emirp because it is prime and its reverse (132134344020131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131020443431231 - 26 = 131020443431167 is a prime.

It is a super-2 number, since 2×1310204434312312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020443431201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510221715615 + 65510221715616.

It is an arithmetic number, because the mean of its divisors is an integer number (65510221715616).

Almost surely, 2131020443431231 is an apocalyptic number.

131020443431231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020443431231 is an equidigital number, since it uses as much as digits as its factorization.

131020443431231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131020443431231 its reverse (132134344020131), we get a palindrome (263154787451362).

The spelling of 131020443431231 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-three million, four hundred thirty-one thousand, two hundred thirty-one".