Base | Representation |
---|---|
bin | 11101110010100110010010… |
… | …111111010011000101001001 |
3 | 122011220102122222100121210220 |
4 | 131302212102333103011021 |
5 | 114133114332004244431 |
6 | 1142353543310100253 |
7 | 36411625504565040 |
oct | 3562462277230511 |
9 | 564812588317726 |
10 | 131020443431241 |
11 | 38824504691641 |
12 | 128407814aa689 |
13 | 58152370654b0 |
14 | 244d5cd759557 |
15 | 102322096cb96 |
hex | 772992fd3149 |
131020443431241 has 32 divisors (see below), whose sum is σ = 216450913324800. Its totient is φ = 68645861040384.
The previous prime is 131020443431231. The next prime is 131020443431243. The reversal of 131020443431241 is 142134344020131.
It is a happy number.
It is not a de Polignac number, because 131020443431241 - 211 = 131020443429193 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131020443431243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1610457190 + ... + 1610538543.
It is an arithmetic number, because the mean of its divisors is an integer number (6764091041400).
Almost surely, 2131020443431241 is an apocalyptic number.
It is an amenable number.
131020443431241 is a deficient number, since it is larger than the sum of its proper divisors (85430469893559).
131020443431241 is a wasteful number, since it uses less digits than its factorization.
131020443431241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3220995905.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 131020443431241 its reverse (142134344020131), we get a palindrome (273154787451372).
The spelling of 131020443431241 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-three million, four hundred thirty-one thousand, two hundred forty-one".
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