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131020443431242 = 2144037454815233
BaseRepresentation
bin11101110010100110010010…
…111111010011000101001010
3122011220102122222100121210221
4131302212102333103011022
5114133114332004244432
61142353543310100254
736411625504565041
oct3562462277230512
9564812588317727
10131020443431242
1138824504691642
12128407814aa68a
1358152370654b1
14244d5cd759558
15102322096cb97
hex772992fd314a

131020443431242 has 8 divisors (see below), whose sum is σ = 196532030024676. Its totient is φ = 65509766756352.

The previous prime is 131020443431231. The next prime is 131020443431243. The reversal of 131020443431242 is 242134344020131.

It can be written as a sum of positive squares in 2 ways, for example, as 124375601969161 + 6644841462081 = 11152381^2 + 2577759^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131020443431198 and 131020443431207.

It is not an unprimeable number, because it can be changed into a prime (131020443431243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227119543 + ... + 227695690.

Almost surely, 2131020443431242 is an apocalyptic number.

131020443431242 is a deficient number, since it is larger than the sum of its proper divisors (65511586593434).

131020443431242 is a wasteful number, since it uses less digits than its factorization.

131020443431242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 454959272.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 131020443431242 its reverse (242134344020131), we get a palindrome (373154787451373).

The spelling of 131020443431242 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-three million, four hundred thirty-one thousand, two hundred forty-two".

Divisors: 1 2 144037 288074 454815233 909630466 65510221715621 131020443431242