13102045243031 has 2 divisors, whose sum is σ = 13102045243032. Its totient is φ = 13102045243030.

The previous prime is 13102045243013. The next prime is 13102045243051. The reversal of 13102045243031 is 13034254020131.

Together with previous prime (13102045243013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102045243031 is a prime.

It is a super-2 number, since 2×13102045243031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13102045242985 and 13102045243003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102045243051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551022621515 + 6551022621516.

It is an arithmetic number, because the mean of its divisors is an integer number (6551022621516).

Almost surely, 2^{13102045243031} is an apocalyptic number.

13102045243031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102045243031 is an equidigital number, since it uses as much as digits as its factorization.

13102045243031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13102045243031 its reverse (13034254020131), we get a palindrome (26136299263162).

The spelling of 13102045243031 in words is "thirteen trillion, one hundred two billion, forty-five million, two hundred forty-three thousand, thirty-one".