131021423201101 has 2 divisors, whose sum is σ = 131021423201102. Its totient is φ = 131021423201100.

The previous prime is 131021423201099. The next prime is 131021423201113. The reversal of 131021423201101 is 101102324120131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111185320358025 + 19836102843076 = 10544445^2 + 4453774^2 .

It is a cyclic number.

It is not a de Polignac number, because 131021423201101 - 2¹ = 131021423201099 is a prime.

It is a super-3 number, since 3×131021423201101³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 131021423201099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131021423201191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510711600550 + 65510711600551.

It is an arithmetic number, because the mean of its divisors is an integer number (65510711600551).

Almost surely, 2^{131021423201101} is an apocalyptic number.

It is an amenable number.

131021423201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021423201101 is an equidigital number, since it uses as much as digits as its factorization.

131021423201101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131021423201101 its reverse (101102324120131), we get a palindrome (232123747321232).

The spelling of 131021423201101 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred twenty-three million, two hundred one thousand, one hundred one".