131021423201401 has 2 divisors, whose sum is σ = 131021423201402. Its totient is φ = 131021423201400.

The previous prime is 131021423201329. The next prime is 131021423201453. The reversal of 131021423201401 is 104102324120131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130198140993600 + 823282207801 = 11410440^2 + 907349^2 .

It is a cyclic number.

It is not a de Polignac number, because 131021423201401 - 2¹¹ = 131021423199353 is a prime.

It is a super-3 number, since 3×131021423201401³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (131021423201101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510711600700 + 65510711600701.

It is an arithmetic number, because the mean of its divisors is an integer number (65510711600701).

Almost surely, 2^{131021423201401} is an apocalyptic number.

It is an amenable number.

131021423201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021423201401 is an equidigital number, since it uses as much as digits as its factorization.

131021423201401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131021423201401 its reverse (104102324120131), we get a palindrome (235123747321532).

The spelling of 131021423201401 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred twenty-three million, two hundred one thousand, four hundred one".