Search a number
-
+
131021424030012 = 22310918452002501
BaseRepresentation
bin11101110010100111001101…
…011011111111000100111100
3122011220112012022112012102220
4131302213031123333010330
5114133123334022430022
61142354224455445340
736411662012542425
oct3562471533770474
9564815168465386
10131021424030012
1138824968163a4a
12128409b5986850
13581536226b959
14244d683a9664c
15102327baba85c
hex7729cd6ff13c

131021424030012 has 12 divisors (see below), whose sum is σ = 305716656070056. Its totient is φ = 43673808010000.

The previous prime is 131021424030011. The next prime is 131021424030019. The reversal of 131021424030012 is 210030424120131.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1310214240300122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131021424030011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5459226001239 + ... + 5459226001262.

It is an arithmetic number, because the mean of its divisors is an integer number (25476388005838).

Almost surely, 2131021424030012 is an apocalyptic number.

131021424030012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131021424030012 is an abundant number, since it is smaller than the sum of its proper divisors (174695232040044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021424030012 is a wasteful number, since it uses less digits than its factorization.

131021424030012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10918452002508 (or 10918452002506 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131021424030012 its reverse (210030424120131), we get a palindrome (341051848150143).

The spelling of 131021424030012 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred twenty-four million, thirty thousand, twelve".

Divisors: 1 2 3 4 6 12 10918452002501 21836904005002 32755356007503 43673808010004 65510712015006 131021424030012