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131022024020453 is a prime number
BaseRepresentation
bin11101110010100111110001…
…001100110001000111100101
3122011220120202010111212121002
4131302213301030301013211
5114133131101122123303
61142354404211403045
736412012616431616
oct3562476114610745
9564816663455532
10131022024020453
1138825145905715
1212840b428b3485
135815429663097
14244d6dd639c0d
1510232b45d5788
hex7729f13311e5

131022024020453 has 2 divisors, whose sum is σ = 131022024020454. Its totient is φ = 131022024020452.

The previous prime is 131022024020431. The next prime is 131022024020473. The reversal of 131022024020453 is 354020420220131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76043684411809 + 54978339608644 = 8720303^2 + 7414738^2 .

It is a cyclic number.

It is not a de Polignac number, because 131022024020453 - 210 = 131022024019429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131022024020473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511012010226 + 65511012010227.

It is an arithmetic number, because the mean of its divisors is an integer number (65511012010227).

Almost surely, 2131022024020453 is an apocalyptic number.

It is an amenable number.

131022024020453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022024020453 is an equidigital number, since it uses as much as digits as its factorization.

131022024020453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 131022024020453 its reverse (354020420220131), we get a palindrome (485042444240584).

The spelling of 131022024020453 in words is "one hundred thirty-one trillion, twenty-two billion, twenty-four million, twenty thousand, four hundred fifty-three".