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131022024020431 is a prime number
BaseRepresentation
bin11101110010100111110001…
…001100110001000111001111
3122011220120202010111212120021
4131302213301030301013033
5114133131101122123211
61142354404211403011
736412012616431555
oct3562476114610717
9564816663455507
10131022024020431
11388251459056a5
1212840b428b3467
13581542966307b
14244d6dd639bd5
1510232b45d5771
hex7729f13311cf

131022024020431 has 2 divisors, whose sum is σ = 131022024020432. Its totient is φ = 131022024020430.

The previous prime is 131022024020429. The next prime is 131022024020453. The reversal of 131022024020431 is 134020420220131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131022024020431 - 21 = 131022024020429 is a prime.

It is a super-2 number, since 2×1310220240204312 (a number of 29 digits) contains 22 as substring.

Together with 131022024020429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131022024020396 and 131022024020405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131022024000431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511012010215 + 65511012010216.

It is an arithmetic number, because the mean of its divisors is an integer number (65511012010216).

Almost surely, 2131022024020431 is an apocalyptic number.

131022024020431 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022024020431 is an equidigital number, since it uses as much as digits as its factorization.

131022024020431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 131022024020431 its reverse (134020420220131), we get a palindrome (265042444240562).

The spelling of 131022024020431 in words is "one hundred thirty-one trillion, twenty-two billion, twenty-four million, twenty thousand, four hundred thirty-one".