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13102203132311 is a prime number
BaseRepresentation
bin1011111010101001100000…
…1010011101100110010111
31201101120002001201120220012
42332222120022131212113
53204131303000213221
643511022524230435
72521413544033226
oct276523012354627
951346061646805
1013102203132311
1141a16821047a7
12157736539b41b
137406bca55137
143342158dacbd
1517ac4200b65b
hexbea9829d997

13102203132311 has 2 divisors, whose sum is σ = 13102203132312. Its totient is φ = 13102203132310.

The previous prime is 13102203132289. The next prime is 13102203132313. The reversal of 13102203132311 is 11323130220131.

It is a strong prime.

It is an emirp because it is prime and its reverse (11323130220131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13102203132311 - 26 = 13102203132247 is a prime.

Together with 13102203132313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102203132313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551101566155 + 6551101566156.

It is an arithmetic number, because the mean of its divisors is an integer number (6551101566156).

Almost surely, 213102203132311 is an apocalyptic number.

13102203132311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102203132311 is an equidigital number, since it uses as much as digits as its factorization.

13102203132311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13102203132311 its reverse (11323130220131), we get a palindrome (24425333352442).

The spelling of 13102203132311 in words is "thirteen trillion, one hundred two billion, two hundred three million, one hundred thirty-two thousand, three hundred eleven".