Base | Representation |
---|---|
bin | 1011111010101001100000… |
… | …1010011101100110010111 |
3 | 1201101120002001201120220012 |
4 | 2332222120022131212113 |
5 | 3204131303000213221 |
6 | 43511022524230435 |
7 | 2521413544033226 |
oct | 276523012354627 |
9 | 51346061646805 |
10 | 13102203132311 |
11 | 41a16821047a7 |
12 | 157736539b41b |
13 | 7406bca55137 |
14 | 3342158dacbd |
15 | 17ac4200b65b |
hex | bea9829d997 |
13102203132311 has 2 divisors, whose sum is σ = 13102203132312. Its totient is φ = 13102203132310.
The previous prime is 13102203132289. The next prime is 13102203132313. The reversal of 13102203132311 is 11323130220131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11323130220131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13102203132311 - 26 = 13102203132247 is a prime.
Together with 13102203132313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102203132313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551101566155 + 6551101566156.
It is an arithmetic number, because the mean of its divisors is an integer number (6551101566156).
Almost surely, 213102203132311 is an apocalyptic number.
13102203132311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102203132311 is an equidigital number, since it uses as much as digits as its factorization.
13102203132311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13102203132311 its reverse (11323130220131), we get a palindrome (24425333352442).
The spelling of 13102203132311 in words is "thirteen trillion, one hundred two billion, two hundred three million, one hundred thirty-two thousand, three hundred eleven".
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