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131022102212101 is a prime number
BaseRepresentation
bin11101110010100111110101…
…110111000010111000000101
3122011220120221120122102101001
4131302213311313002320011
5114133131231131241401
61142354420043333301
736412014556153612
oct3562476567027005
9564816846572331
10131022102212101
1138825185a61211
1212840b64b21231
13581543c90c329
14244d709b91509
1510232bb3cd601
hex7729f5dc2e05

131022102212101 has 2 divisors, whose sum is σ = 131022102212102. Its totient is φ = 131022102212100.

The previous prime is 131022102212093. The next prime is 131022102212137. The reversal of 131022102212101 is 101212201220131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111872717460100 + 19149384752001 = 10576990^2 + 4376001^2 .

It is a cyclic number.

It is not a de Polignac number, because 131022102212101 - 23 = 131022102212093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131022102212171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511051106050 + 65511051106051.

It is an arithmetic number, because the mean of its divisors is an integer number (65511051106051).

Almost surely, 2131022102212101 is an apocalyptic number.

It is an amenable number.

131022102212101 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022102212101 is an equidigital number, since it uses as much as digits as its factorization.

131022102212101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 131022102212101 its reverse (101212201220131), we get a palindrome (232234303432232).

The spelling of 131022102212101 in words is "one hundred thirty-one trillion, twenty-two billion, one hundred two million, two hundred twelve thousand, one hundred one".