13102211231 has 2 divisors, whose sum is σ = 13102211232. Its totient is φ = 13102211230.

The previous prime is 13102211209. The next prime is 13102211233. The reversal of 13102211231 is 13211220131.

It is a strong prime.

It is an emirp because it is prime and its reverse (13211220131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13102211231 - 2¹⁸ = 13101949087 is a prime.

It is a super-2 number, since 2×13102211231² (a number of 21 digits) contains 22 as substring.

Together with 13102211233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102211233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551105615 + 6551105616.

It is an arithmetic number, because the mean of its divisors is an integer number (6551105616).

Almost surely, 2^13102211231 is an apocalyptic number.

13102211231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102211231 is an equidigital number, since it uses as much as digits as its factorization.

13102211231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13102211231 its reverse (13211220131), we get a palindrome (26313431362).

The spelling of 13102211231 in words is "thirteen billion, one hundred two million, two hundred eleven thousand, two hundred thirty-one".