Base | Representation |
---|---|
bin | 111101000000110001… |
… | …0100010100001010111 |
3 | 110112012011122012021111 |
4 | 1322001202202201113 |
5 | 4121313204142124 |
6 | 140105115155451 |
7 | 12315566315032 |
oct | 1720142424127 |
9 | 415164565244 |
10 | 131022334039 |
11 | 506257678a3 |
12 | 21487145b87 |
13 | c48093160c |
14 | 64ad18c019 |
15 | 361c9a7494 |
hex | 1e818a2857 |
131022334039 has 2 divisors, whose sum is σ = 131022334040. Its totient is φ = 131022334038.
The previous prime is 131022333997. The next prime is 131022334049. The reversal of 131022334039 is 930433220131.
It is a strong prime.
It is an emirp because it is prime and its reverse (930433220131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131022334039 - 233 = 122432399447 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131022334039.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131022334049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511167019 + 65511167020.
It is an arithmetic number, because the mean of its divisors is an integer number (65511167020).
Almost surely, 2131022334039 is an apocalyptic number.
131022334039 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022334039 is an equidigital number, since it uses as much as digits as its factorization.
131022334039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 131022334039 in words is "one hundred thirty-one billion, twenty-two million, three hundred thirty-four thousand, thirty-nine".
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