Base | Representation |
---|---|
bin | 111101000000110001… |
… | …0100010100001100001 |
3 | 110112012011122012021212 |
4 | 1322001202202201201 |
5 | 4121313204142144 |
6 | 140105115155505 |
7 | 12315566315045 |
oct | 1720142424141 |
9 | 415164565255 |
10 | 131022334049 |
11 | 50625767902 |
12 | 21487145b95 |
13 | c480931619 |
14 | 64ad18c025 |
15 | 361c9a749e |
hex | 1e818a2861 |
131022334049 has 2 divisors, whose sum is σ = 131022334050. Its totient is φ = 131022334048.
The previous prime is 131022334039. The next prime is 131022334063. The reversal of 131022334049 is 940433220131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126778723600 + 4243610449 = 356060^2 + 65143^2 .
It is an emirp because it is prime and its reverse (940433220131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131022334049 - 212 = 131022329953 is a prime.
It is not a weakly prime, because it can be changed into another prime (131022334039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511167024 + 65511167025.
It is an arithmetic number, because the mean of its divisors is an integer number (65511167025).
Almost surely, 2131022334049 is an apocalyptic number.
It is an amenable number.
131022334049 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022334049 is an equidigital number, since it uses as much as digits as its factorization.
131022334049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 131022334049 in words is "one hundred thirty-one billion, twenty-two million, three hundred thirty-four thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •