Base | Representation |
---|---|
bin | 1011111010101001111101… |
… | …1000011101110000001111 |
3 | 1201101120101111121200011201 |
4 | 2332222133120131300033 |
5 | 3204132030001242341 |
6 | 43511042532130331 |
7 | 2521416544333051 |
oct | 276523730356017 |
9 | 51346344550151 |
10 | 13102324243471 |
11 | 41a1734505371 |
12 | 1577399a669a7 |
13 | 74070bb7aa48 |
14 | 334227a258d1 |
15 | 17ac4c981331 |
hex | bea9f61dc0f |
13102324243471 has 2 divisors, whose sum is σ = 13102324243472. Its totient is φ = 13102324243470.
The previous prime is 13102324243387. The next prime is 13102324243499. The reversal of 13102324243471 is 17434242320131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13102324243471 is a prime.
It is a super-3 number, since 3×131023242434713 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 13102324243471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102324243171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551162121735 + 6551162121736.
It is an arithmetic number, because the mean of its divisors is an integer number (6551162121736).
Almost surely, 213102324243471 is an apocalyptic number.
13102324243471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102324243471 is an equidigital number, since it uses as much as digits as its factorization.
13102324243471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 37.
The spelling of 13102324243471 in words is "thirteen trillion, one hundred two billion, three hundred twenty-four million, two hundred forty-three thousand, four hundred seventy-one".
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