Base | Representation |
---|---|
bin | 111101000000110011… |
… | …0010110001010111111 |
3 | 110112012020111220021011 |
4 | 1322001212112022333 |
5 | 4121313433111111 |
6 | 140105152420051 |
7 | 12315610642444 |
oct | 1720146261277 |
9 | 415166456234 |
10 | 131023332031 |
11 | 50626289689 |
12 | 21487547627 |
13 | c480bc0947 |
14 | 64ad36b9cb |
15 | 361cb03021 |
hex | 1e819962bf |
131023332031 has 2 divisors, whose sum is σ = 131023332032. Its totient is φ = 131023332030.
The previous prime is 131023331987. The next prime is 131023332047. The reversal of 131023332031 is 130233320131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131023332031 - 221 = 131021234879 is a prime.
It is a super-2 number, since 2×1310233320312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131023331993 and 131023332011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131023332091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511666015 + 65511666016.
It is an arithmetic number, because the mean of its divisors is an integer number (65511666016).
Almost surely, 2131023332031 is an apocalyptic number.
131023332031 is a deficient number, since it is larger than the sum of its proper divisors (1).
131023332031 is an equidigital number, since it uses as much as digits as its factorization.
131023332031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 131023332031 its reverse (130233320131), we get a palindrome (261256652162).
The spelling of 131023332031 in words is "one hundred thirty-one billion, twenty-three million, three hundred thirty-two thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •