1310240042134 has 4 divisors (see below), whose sum is σ = 1965360063204. Its totient is φ = 655120021066.

The previous prime is 1310240042129. The next prime is 1310240042143. The reversal of 1310240042134 is 4312400420131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1310240042134² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310240042099 and 1310240042108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327560010532 + ... + 327560010535.

It is an arithmetic number, because the mean of its divisors is an integer number (491340015801).

Almost surely, 2^{1310240042134} is an apocalyptic number.

1310240042134 is a deficient number, since it is larger than the sum of its proper divisors (655120021070).

1310240042134 is an equidigital number, since it uses as much as digits as its factorization.

1310240042134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655120021069.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1310240042134 its reverse (4312400420131), we get a palindrome (5622640462265).

The spelling of 1310240042134 in words is "one trillion, three hundred ten billion, two hundred forty million, forty-two thousand, one hundred thirty-four".