Base | Representation |
---|---|
bin | 10011000100010000011… |
… | …001000110110010011111 |
3 | 11122020221212210111021021 |
4 | 103010100121012302133 |
5 | 132431332422322033 |
6 | 2441525503145011 |
7 | 163442653412554 |
oct | 23042031066237 |
9 | 4566855714237 |
10 | 1310240042143 |
11 | 46574038943a |
12 | 191b248a5167 |
13 | 9672a74b986 |
14 | 475b7554a2b |
15 | 24137debb2d |
hex | 13110646c9f |
1310240042143 has 2 divisors, whose sum is σ = 1310240042144. Its totient is φ = 1310240042142.
The previous prime is 1310240042129. The next prime is 1310240042183. The reversal of 1310240042143 is 3412400420131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310240042143 - 29 = 1310240041631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310240042183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120021071 + 655120021072.
It is an arithmetic number, because the mean of its divisors is an integer number (655120021072).
Almost surely, 21310240042143 is an apocalyptic number.
1310240042143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310240042143 is an equidigital number, since it uses as much as digits as its factorization.
1310240042143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1310240042143 its reverse (3412400420131), we get a palindrome (4722640462274).
The spelling of 1310240042143 in words is "one trillion, three hundred ten billion, two hundred forty million, forty-two thousand, one hundred forty-three".
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