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1310240042143 is a prime number
BaseRepresentation
bin10011000100010000011…
…001000110110010011111
311122020221212210111021021
4103010100121012302133
5132431332422322033
62441525503145011
7163442653412554
oct23042031066237
94566855714237
101310240042143
1146574038943a
12191b248a5167
139672a74b986
14475b7554a2b
1524137debb2d
hex13110646c9f

1310240042143 has 2 divisors, whose sum is σ = 1310240042144. Its totient is φ = 1310240042142.

The previous prime is 1310240042129. The next prime is 1310240042183. The reversal of 1310240042143 is 3412400420131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310240042143 - 29 = 1310240041631 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310240042183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120021071 + 655120021072.

It is an arithmetic number, because the mean of its divisors is an integer number (655120021072).

Almost surely, 21310240042143 is an apocalyptic number.

1310240042143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310240042143 is an equidigital number, since it uses as much as digits as its factorization.

1310240042143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1310240042143 its reverse (3412400420131), we get a palindrome (4722640462274).

The spelling of 1310240042143 in words is "one trillion, three hundred ten billion, two hundred forty million, forty-two thousand, one hundred forty-three".