Base | Representation |
---|---|
bin | 11101110010110000001010… |
… | …110001100001010101110111 |
3 | 122011221110000200100112021221 |
4 | 131302300022301201111313 |
5 | 114133303034003121101 |
6 | 1142402455152051211 |
7 | 36412452252604441 |
oct | 3562601261412567 |
9 | 564843020315257 |
10 | 131031043020151 |
11 | 38828a538a367a |
12 | 1284283b233b07 |
13 | 58162360363b1 |
14 | 244dd17399491 |
15 | 10236412b6aa1 |
hex | 772c0ac61577 |
131031043020151 has 2 divisors, whose sum is σ = 131031043020152. Its totient is φ = 131031043020150.
The previous prime is 131031043020127. The next prime is 131031043020209. The reversal of 131031043020151 is 151020340130131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131031043020151 - 231 = 131028895536503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131031043020751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515521510075 + 65515521510076.
It is an arithmetic number, because the mean of its divisors is an integer number (65515521510076).
Almost surely, 2131031043020151 is an apocalyptic number.
131031043020151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031043020151 is an equidigital number, since it uses as much as digits as its factorization.
131031043020151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 131031043020151 its reverse (151020340130131), we get a palindrome (282051383150282).
The spelling of 131031043020151 in words is "one hundred thirty-one trillion, thirty-one billion, forty-three million, twenty thousand, one hundred fifty-one".
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