Base | Representation |
---|---|
bin | 10011000100010100100… |
… | …110000010110010100111 |
3 | 11122021010210110021120201 |
4 | 103010110212002302213 |
5 | 132432003444330003 |
6 | 2441540502211331 |
7 | 163444500562144 |
oct | 23042446026247 |
9 | 4567123407521 |
10 | 1310310542503 |
11 | 4657771613a6 |
12 | 191b44423b47 |
13 | 9673c234171 |
14 | 475c2a673cb |
15 | 2413e1c5b1d |
hex | 13114982ca7 |
1310310542503 has 2 divisors, whose sum is σ = 1310310542504. Its totient is φ = 1310310542502.
The previous prime is 1310310542491. The next prime is 1310310542509. The reversal of 1310310542503 is 3052450130131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310310542503 - 213 = 1310310534311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310310542509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655155271251 + 655155271252.
It is an arithmetic number, because the mean of its divisors is an integer number (655155271252).
Almost surely, 21310310542503 is an apocalyptic number.
1310310542503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310310542503 is an equidigital number, since it uses as much as digits as its factorization.
1310310542503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1310310542503 its reverse (3052450130131), we get a palindrome (4362760672634).
The spelling of 1310310542503 in words is "one trillion, three hundred ten billion, three hundred ten million, five hundred forty-two thousand, five hundred three".
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