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1310310542503 is a prime number
BaseRepresentation
bin10011000100010100100…
…110000010110010100111
311122021010210110021120201
4103010110212002302213
5132432003444330003
62441540502211331
7163444500562144
oct23042446026247
94567123407521
101310310542503
114657771613a6
12191b44423b47
139673c234171
14475c2a673cb
152413e1c5b1d
hex13114982ca7

1310310542503 has 2 divisors, whose sum is σ = 1310310542504. Its totient is φ = 1310310542502.

The previous prime is 1310310542491. The next prime is 1310310542509. The reversal of 1310310542503 is 3052450130131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310310542503 - 213 = 1310310534311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310310542509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655155271251 + 655155271252.

It is an arithmetic number, because the mean of its divisors is an integer number (655155271252).

Almost surely, 21310310542503 is an apocalyptic number.

1310310542503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310310542503 is an equidigital number, since it uses as much as digits as its factorization.

1310310542503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 1310310542503 its reverse (3052450130131), we get a palindrome (4362760672634).

The spelling of 1310310542503 in words is "one trillion, three hundred ten billion, three hundred ten million, five hundred forty-two thousand, five hundred three".