13103111040330 has 16 divisors (see below), whose sum is σ = 31447466496864. Its totient is φ = 3494162944080.

The previous prime is 13103111040329. The next prime is 13103111040343. The reversal of 13103111040330 is 3304011130131.

It is a junction number, because it is equal to n+sod(n) for n = 13103111040297 and 13103111040306.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218385183976 + ... + 218385184035.

It is an arithmetic number, because the mean of its divisors is an integer number (1965466656054).

Almost surely, 2^{13103111040330} is an apocalyptic number.

13103111040330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13103111040330 is an abundant number, since it is smaller than the sum of its proper divisors (18344355456534).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103111040330 is a wasteful number, since it uses less digits than its factorization.

13103111040330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436770368021.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 13103111040330 its reverse (3304011130131), we get a palindrome (16407122170461).

The spelling of 13103111040330 in words is "thirteen trillion, one hundred three billion, one hundred eleven million, forty thousand, three hundred thirty".