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13103111040343 is a prime number
BaseRepresentation
bin1011111010101100111001…
…0001110110110101010111
31201101122102100010002120121
42332223032101312311113
53204140132411242333
643511253000012411
72521445210106352
oct276531621666527
951348370102517
1013103111040343
1141a1aa8648515
121577579461107
13740805b8a11c
143342a0315299
1517ac96a9b32d
hexbeace476d57

13103111040343 has 2 divisors, whose sum is σ = 13103111040344. Its totient is φ = 13103111040342.

The previous prime is 13103111040329. The next prime is 13103111040389. The reversal of 13103111040343 is 34304011130131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13103111040343 is a prime.

It is a super-3 number, since 3×131031110403433 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103111040323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551555520171 + 6551555520172.

It is an arithmetic number, because the mean of its divisors is an integer number (6551555520172).

Almost surely, 213103111040343 is an apocalyptic number.

13103111040343 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103111040343 is an equidigital number, since it uses as much as digits as its factorization.

13103111040343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13103111040343 its reverse (34304011130131), we get a palindrome (47407122170474).

The spelling of 13103111040343 in words is "thirteen trillion, one hundred three billion, one hundred eleven million, forty thousand, three hundred forty-three".