Base | Representation |
---|---|
bin | 1011111010101100111001… |
… | …0001110110110101010111 |
3 | 1201101122102100010002120121 |
4 | 2332223032101312311113 |
5 | 3204140132411242333 |
6 | 43511253000012411 |
7 | 2521445210106352 |
oct | 276531621666527 |
9 | 51348370102517 |
10 | 13103111040343 |
11 | 41a1aa8648515 |
12 | 1577579461107 |
13 | 740805b8a11c |
14 | 3342a0315299 |
15 | 17ac96a9b32d |
hex | beace476d57 |
13103111040343 has 2 divisors, whose sum is σ = 13103111040344. Its totient is φ = 13103111040342.
The previous prime is 13103111040329. The next prime is 13103111040389. The reversal of 13103111040343 is 34304011130131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13103111040343 is a prime.
It is a super-3 number, since 3×131031110403433 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13103111040323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551555520171 + 6551555520172.
It is an arithmetic number, because the mean of its divisors is an integer number (6551555520172).
Almost surely, 213103111040343 is an apocalyptic number.
13103111040343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103111040343 is an equidigital number, since it uses as much as digits as its factorization.
13103111040343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13103111040343 its reverse (34304011130131), we get a palindrome (47407122170474).
The spelling of 13103111040343 in words is "thirteen trillion, one hundred three billion, one hundred eleven million, forty thousand, three hundred forty-three".
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