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131031111032357 is a prime number
BaseRepresentation
bin11101110010110000001110…
…110100111101111000100101
3122011221110012102022220111112
4131302300032310331320211
5114133303203411013412
61142402510021514405
736412454036651654
oct3562601664757045
9564843172286445
10131031111032357
1138828a89227208
1212842859b72a05
13581624715a1c3
14244dd2242119b
15102364724d722
hex772c0ed3de25

131031111032357 has 2 divisors, whose sum is σ = 131031111032358. Its totient is φ = 131031111032356.

The previous prime is 131031111032309. The next prime is 131031111032363. The reversal of 131031111032357 is 753230111130131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112623012535201 + 18408098497156 = 10612399^2 + 4290466^2 .

It is an emirp because it is prime and its reverse (753230111130131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131031111032357 - 234 = 131013931163173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131031119032357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515555516178 + 65515555516179.

It is an arithmetic number, because the mean of its divisors is an integer number (65515555516179).

Almost surely, 2131031111032357 is an apocalyptic number.

It is an amenable number.

131031111032357 is a deficient number, since it is larger than the sum of its proper divisors (1).

131031111032357 is an equidigital number, since it uses as much as digits as its factorization.

131031111032357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5670, while the sum is 32.

Adding to 131031111032357 its reverse (753230111130131), we get a palindrome (884261222162488).

The spelling of 131031111032357 in words is "one hundred thirty-one trillion, thirty-one billion, one hundred eleven million, thirty-two thousand, three hundred fifty-seven".