Base | Representation |
---|---|
bin | 1011111010101101001110… |
… | …0101001101100001111000 |
3 | 1201101122122112111201110011 |
4 | 2332223103211031201320 |
5 | 3204140323200000440 |
6 | 43511305454431304 |
7 | 2521450340210326 |
oct | 276532345154170 |
9 | 51348575451404 |
10 | 13103200000120 |
11 | 41a204388929a |
12 | 15775a3202534 |
13 | 74081b436749 |
14 | 3342ac070d16 |
15 | 17ac9e7be9ea |
hex | bead394d878 |
13103200000120 has 16 divisors (see below), whose sum is σ = 29482200000360. Its totient is φ = 5241280000032.
The previous prime is 13103200000031. The next prime is 13103200000141. The reversal of 13103200000120 is 2100000230131.
It is a super-3 number, since 3×131032000001203 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13103200000120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163789999962 + ... + 163790000041.
Almost surely, 213103200000120 is an apocalyptic number.
13103200000120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13103200000120 is an abundant number, since it is smaller than the sum of its proper divisors (16379000000240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103200000120 is a wasteful number, since it uses less digits than its factorization.
13103200000120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327580000014 (or 327580000010 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 13103200000120 its reverse (2100000230131), we get a palindrome (15203200230251).
The spelling of 13103200000120 in words is "thirteen trillion, one hundred three billion, two hundred million, one hundred twenty", and thus it is an aban number.
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