Base | Representation |
---|---|
bin | 10011000100010101010… |
… | …101101110000010011101 |
3 | 11122021011122222020111021 |
4 | 103010111111232002131 |
5 | 132432020144243123 |
6 | 2441542030124141 |
7 | 163445012034202 |
oct | 23042525560235 |
9 | 4567148866437 |
10 | 1310323040413 |
11 | 465783218252 |
12 | 191b48650651 |
13 | 967419bb98a |
14 | 475c459bca9 |
15 | 24140343c5d |
hex | 1311556e09d |
1310323040413 has 2 divisors, whose sum is σ = 1310323040414. Its totient is φ = 1310323040412.
The previous prime is 1310323040387. The next prime is 1310323040483. The reversal of 1310323040413 is 3140403230131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1260237495609 + 50085544804 = 1122603^2 + 223798^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310323040413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310323040483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655161520206 + 655161520207.
It is an arithmetic number, because the mean of its divisors is an integer number (655161520207).
Almost surely, 21310323040413 is an apocalyptic number.
It is an amenable number.
1310323040413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310323040413 is an equidigital number, since it uses as much as digits as its factorization.
1310323040413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1310323040413 its reverse (3140403230131), we get a palindrome (4450726270544).
The spelling of 1310323040413 in words is "one trillion, three hundred ten billion, three hundred twenty-three million, forty thousand, four hundred thirteen".
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