13103301303119 has 2 divisors, whose sum is σ = 13103301303120. Its totient is φ = 13103301303118.

The previous prime is 13103301303011. The next prime is 13103301303121. The reversal of 13103301303119 is 91130310330131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13103301303119 - 2²⁰ = 13103300254543 is a prime.

It is a super-2 number, since 2×13103301303119² (a number of 27 digits) contains 22 as substring.

Together with 13103301303121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13103301303091 and 13103301303100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103301303919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551650651559 + 6551650651560.

It is an arithmetic number, because the mean of its divisors is an integer number (6551650651560).

Almost surely, 2^{13103301303119} is an apocalyptic number.

13103301303119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103301303119 is an equidigital number, since it uses as much as digits as its factorization.

13103301303119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 29.

The spelling of 13103301303119 in words is "thirteen trillion, one hundred three billion, three hundred one million, three hundred three thousand, one hundred nineteen".