131040300023130 has 32 divisors (see below), whose sum is σ = 314501615541504. Its totient is φ = 34943536063296.

The previous prime is 131040300023111. The next prime is 131040300023147. The reversal of 131040300023130 is 31320003040131.

It is a junction number, because it is equal to n+sod(n) for n = 131040300023097 and 131040300023106.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32035189 + ... + 35893368.

It is an arithmetic number, because the mean of its divisors is an integer number (9828175485672).

Almost surely, 2^{131040300023130} is an apocalyptic number.

131040300023130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131040300023130 is an abundant number, since it is smaller than the sum of its proper divisors (183461315518374).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131040300023130 is a wasteful number, since it uses less digits than its factorization.

131040300023130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67992870.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 131040300023130 its reverse (31320003040131), we get a palindrome (162360303063261).

The spelling of 131040300023130 in words is "one hundred thirty-one trillion, forty billion, three hundred million, twenty-three thousand, one hundred thirty".