Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …0111101001010001101011 |
3 | 1201101201222102120001202221 |
4 | 2332230021113221101223 |
5 | 3204144200204212134 |
6 | 43511535212334511 |
7 | 2521511605460023 |
oct | 276541127512153 |
9 | 51351872501687 |
10 | 13104102413419 |
11 | 41a2467209806 |
12 | 15777b5474437 |
13 | 740933396704 |
14 | 334355c58a83 |
15 | 17ad03b265b4 |
hex | beb095e946b |
13104102413419 has 2 divisors, whose sum is σ = 13104102413420. Its totient is φ = 13104102413418.
The previous prime is 13104102413383. The next prime is 13104102413453. The reversal of 13104102413419 is 91431420140131.
It is an a-pointer prime, because the next prime (13104102413453) can be obtained adding 13104102413419 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13104102413419 - 211 = 13104102411371 is a prime.
It is a super-2 number, since 2×131041024134192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13104102410419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552051206709 + 6552051206710.
It is an arithmetic number, because the mean of its divisors is an integer number (6552051206710).
Almost surely, 213104102413419 is an apocalyptic number.
13104102413419 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104102413419 is an equidigital number, since it uses as much as digits as its factorization.
13104102413419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 13104102413419 in words is "thirteen trillion, one hundred four billion, one hundred two million, four hundred thirteen thousand, four hundred nineteen".
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