Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …1011000100011101110111 |
3 | 1201101201222111020200022221 |
4 | 2332230021123010131313 |
5 | 3204144200421424343 |
6 | 43511535243503211 |
7 | 2521511616216361 |
oct | 276541133043567 |
9 | 51351874220287 |
10 | 13104103311223 |
11 | 41a24677722a1 |
12 | 15777b5827b07 |
13 | 74093361c262 |
14 | 33435600dd31 |
15 | 17ad03c525ed |
hex | beb096c4777 |
13104103311223 has 2 divisors, whose sum is σ = 13104103311224. Its totient is φ = 13104103311222.
The previous prime is 13104103311113. The next prime is 13104103311269. The reversal of 13104103311223 is 32211330140131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104103311223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104103311323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552051655611 + 6552051655612.
It is an arithmetic number, because the mean of its divisors is an integer number (6552051655612).
Almost surely, 213104103311223 is an apocalyptic number.
13104103311223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104103311223 is an equidigital number, since it uses as much as digits as its factorization.
13104103311223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13104103311223 its reverse (32211330140131), we get a palindrome (45315433451354).
The spelling of 13104103311223 in words is "thirteen trillion, one hundred four billion, one hundred three million, three hundred eleven thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •