Base | Representation |
---|---|
bin | 10011000100011011011… |
… | …010101101111010001111 |
3 | 11122021102202212000211012 |
4 | 103010123122231322033 |
5 | 132432222300421103 |
6 | 2442000111515435 |
7 | 163450360556045 |
oct | 23043332557217 |
9 | 4567382760735 |
10 | 1310425013903 |
11 | 465825837465 |
12 | 191b76828b7b |
13 | 96759b73815 |
14 | 475d3d44395 |
15 | 241492882d8 |
hex | 1311b6ade8f |
1310425013903 has 2 divisors, whose sum is σ = 1310425013904. Its totient is φ = 1310425013902.
The previous prime is 1310425013893. The next prime is 1310425013921. The reversal of 1310425013903 is 3093105240131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310425013903 - 28 = 1310425013647 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1310425013903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310425015903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655212506951 + 655212506952.
It is an arithmetic number, because the mean of its divisors is an integer number (655212506952).
Almost surely, 21310425013903 is an apocalyptic number.
1310425013903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310425013903 is an equidigital number, since it uses as much as digits as its factorization.
1310425013903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 32.
The spelling of 1310425013903 in words is "one trillion, three hundred ten billion, four hundred twenty-five million, thirteen thousand, nine hundred three".
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