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1310430134230 = 25718720430489
BaseRepresentation
bin10011000100011011101…
…110001111111111010110
311122021110010111011120221
4103010123232033333112
5132432230103243410
62442000413344554
7163450452233110
oct23043356177726
94567403434527
101310430134230
11465828714438
12191b7849815a
139675ac472b9
14475d48b83b0
152414994a4da
hex1311bb8ffd6

1310430134230 has 16 divisors (see below), whose sum is σ = 2695741990560. Its totient is φ = 449290331712.

The previous prime is 1310430134201. The next prime is 1310430134239. The reversal of 1310430134230 is 324310340131.

It is a junction number, because it is equal to n+sod(n) for n = 1310430134195 and 1310430134204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310430134239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9360215175 + ... + 9360215314.

It is an arithmetic number, because the mean of its divisors is an integer number (168483874410).

Almost surely, 21310430134230 is an apocalyptic number.

1310430134230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310430134230 is an abundant number, since it is smaller than the sum of its proper divisors (1385311856330).

1310430134230 is a wasteful number, since it uses less digits than its factorization.

1310430134230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18720430503.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1310430134230 its reverse (324310340131), we get a palindrome (1634740474361).

The spelling of 1310430134230 in words is "one trillion, three hundred ten billion, four hundred thirty million, one hundred thirty-four thousand, two hundred thirty".

Divisors: 1 2 5 7 10 14 35 70 18720430489 37440860978 93602152445 131043013423 187204304890 262086026846 655215067115 1310430134230