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13104311030341 is a prime number
BaseRepresentation
bin1011111010110001010111…
…0011011101001001000101
31201101202111222002220101121
42332230111303131021011
53204200112110432331
643512012023553541
72521520020623436
oct276542563351105
951352458086347
1013104311030341
1141a2563a47793
1215778532bb8b1
13740967679b8b
1433437584148d
1517ad170d3c11
hexbeb15cdd245

13104311030341 has 2 divisors, whose sum is σ = 13104311030342. Its totient is φ = 13104311030340.

The previous prime is 13104311030311. The next prime is 13104311030357. The reversal of 13104311030341 is 14303011340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12430179717316 + 674131313025 = 3525646^2 + 821055^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104311030341 - 29 = 13104311029829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104311030311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552155515170 + 6552155515171.

It is an arithmetic number, because the mean of its divisors is an integer number (6552155515171).

Almost surely, 213104311030341 is an apocalyptic number.

It is an amenable number.

13104311030341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104311030341 is an equidigital number, since it uses as much as digits as its factorization.

13104311030341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13104311030341 its reverse (14303011340131), we get a palindrome (27407322370472).

The spelling of 13104311030341 in words is "thirteen trillion, one hundred four billion, three hundred eleven million, thirty thousand, three hundred forty-one".