Base | Representation |
---|---|
bin | 10011000100011011110… |
… | …110111001011110111001 |
3 | 11122021110021202100110212 |
4 | 103010123312321132321 |
5 | 132432231143320322 |
6 | 2442000534120505 |
7 | 163450510424543 |
oct | 23043366713671 |
9 | 4567407670425 |
10 | 1310432401337 |
11 | 465829a22784 |
12 | 191b791b0135 |
13 | 9675b55c197 |
14 | 475d4d08693 |
15 | 24149c470e2 |
hex | 1311bdb97b9 |
1310432401337 has 2 divisors, whose sum is σ = 1310432401338. Its totient is φ = 1310432401336.
The previous prime is 1310432401297. The next prime is 1310432401339. The reversal of 1310432401337 is 7331042340131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1251420331561 + 59012069776 = 1118669^2 + 242924^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310432401337 - 26 = 1310432401273 is a prime.
Together with 1310432401339, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1310432401339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216200668 + 655216200669.
It is an arithmetic number, because the mean of its divisors is an integer number (655216200669).
Almost surely, 21310432401337 is an apocalyptic number.
It is an amenable number.
1310432401337 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310432401337 is an equidigital number, since it uses as much as digits as its factorization.
1310432401337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 1310432401337 its reverse (7331042340131), we get a palindrome (8641474741468).
The spelling of 1310432401337 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, four hundred one thousand, three hundred thirty-seven".
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