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131043252313 is a prime number
BaseRepresentation
bin111101000001011001…
…0010101100001011001
3110112020121222221202101
41322002302111201121
54121334033033223
6140111143403401
712316242160201
oct1720262254131
9415217887671
10131043252313
1150636555026
1221492153561
13c4850769ac
1464b1c75401
15361e73a4ad
hex1e82c95859

131043252313 has 2 divisors, whose sum is σ = 131043252314. Its totient is φ = 131043252312.

The previous prime is 131043252311. The next prime is 131043252343. The reversal of 131043252313 is 313252340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110271813184 + 20771439129 = 332072^2 + 144123^2 .

It is a cyclic number.

It is not a de Polignac number, because 131043252313 - 21 = 131043252311 is a prime.

Together with 131043252311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131043252311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521626156 + 65521626157.

It is an arithmetic number, because the mean of its divisors is an integer number (65521626157).

Almost surely, 2131043252313 is an apocalyptic number.

It is an amenable number.

131043252313 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043252313 is an equidigital number, since it uses as much as digits as its factorization.

131043252313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 131043252313 its reverse (313252340131), we get a palindrome (444295592444).

The spelling of 131043252313 in words is "one hundred thirty-one billion, forty-three million, two hundred fifty-two thousand, three hundred thirteen".