Base | Representation |
---|---|
bin | 1011111010110001011111… |
… | …0010011011000001111011 |
3 | 1201101202121021201212221221 |
4 | 2332230113302123001323 |
5 | 3204200144121021404 |
6 | 43512015213212511 |
7 | 2521520603546332 |
oct | 276542762330173 |
9 | 51352537655857 |
10 | 13104344313979 |
11 | 41a2580810226 |
12 | 1577862491137 |
13 | 740971531639 |
14 | 33437a026d19 |
15 | 17ad19eaa954 |
hex | beb17c9b07b |
13104344313979 has 2 divisors, whose sum is σ = 13104344313980. Its totient is φ = 13104344313978.
The previous prime is 13104344313967. The next prime is 13104344314031. The reversal of 13104344313979 is 97931344340131.
It is an a-pointer prime, because the next prime (13104344314031) can be obtained adding 13104344313979 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104344313979 - 211 = 13104344311931 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104344313079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552172156989 + 6552172156990.
It is an arithmetic number, because the mean of its divisors is an integer number (6552172156990).
Almost surely, 213104344313979 is an apocalyptic number.
13104344313979 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104344313979 is an equidigital number, since it uses as much as digits as its factorization.
13104344313979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328, while the sum is 52.
The spelling of 13104344313979 in words is "thirteen trillion, one hundred four billion, three hundred forty-four million, three hundred thirteen thousand, nine hundred seventy-nine".
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